Jon pushes a lawnmower with a force of 50.0 N directed at 50 degrees from the horizontal. The lawn mower moves 90.0 m. If Jon took 10.0 minutes to mow 90.0 - 11729279

get priceEmail Contact26/09/2021 Jon pushes a lawnmower with a force of 50.0 n directed at 50 degrees from the horizontal. the lawn mower moves 90.0 m. if jon took 10.0 minutes to mow 90.0 m of grass, what was his power in si units?

get priceEmail ContactCorrect answers: 1 question: Jon pushes a lawnmower with a force of 50.0 n directed at 50 degrees from the horizontal. the lawn mower moves 90.0 m. if jon took 10.0 minutes to mow 90.0 m of grass, what was his power in si units?

get priceEmail Contact11/02/2014 Work Problem -- Pushing a lawnmower 1. A lawn mower (25kg) is pushed a horizontal distance of 10m by a 50 N downward force directed 60 degrees to the horizontal. The coefficient of kinetic frictional force is .017. What is the work done by each of the external forces on the lawn mower...

get priceEmail ContactJon pushes a lawnmower with a force of 50.0 N directed at 50 degrees from the horizontal. The lawn mower moves 90.0 m. If Jon to. Gnom [1K] F = force by which Jon pushes the lawnmower = 50.0 N . θ = Angle of the force applied with the horizontal = 50 degrees. d = displacement of the lawnmower due to force applied = 90.0 W = work done on the

get priceEmail ContactShe pushes the mower with a force of 150 N directed at an angle of 30° below the horizontal direction. Calculate the work Mona does on the mower each time she pushes it 10.0 m across the yard. Question: Mona is cutting the grass using a 50.0-kg human-powered lawn mower. She pushes the mower with a force of 150 N directed at an angle of 30° below the horizontal

get priceEmail ContactAns. W = F × d = 25 N × 20.0 m = 50 J 2. A force of 120 N is applied to the front of a sled at an angle of 28.0 above the horizontal so as to pull the sled a distance of 165 meters. How much work was done by the applied force? Ans. W = F •d cos = 120 N • 165 m cos 28.0 = 17,482.36 J 3. A sled, which has a mass of 45.0 kg., is sitting on a horizontal surface. A force of 120 N is

get priceEmail ContactA 10-N force is applied to push a block across a friction free surface for a displacement of 5.0 m to the right. See Answer Only F app does work. F grav and F norm do not do work since a vertical force cannot cause a horizontal displacement. See Answer W app = (10 N) * (5 m) *cos (0 degrees) = +50 Joules. A 10-N frictional force slows a moving block to a stop after a

get priceEmail Contact31/01/2010 A person pushes a 14.0-kg lawn mower at constant speed with a force of F = 88.0N directed along the handle, which is set at an angle of 45 degrees to the horizontal. (a) Draw the free-body diagram showing all forces acting on the mower. Calculate (b) the horizontal friction force on the mower, then (c) the normal force exerted vertically upward ...

get priceEmail Contact27/03/2018 F_x=35sqrt3 N F_y=35 N To put it shortly, any force F making an angle theta with the horizontal has x and y components Fcos(theta) and Fsin(theta) "Detailed explanation:" He is pulling his dog at an angle of 30 with the horizontal with a force of 70 N There are an x component and a y component to this force If we draw this as a vector, then the diagram

get priceEmail ContactCorrect answer to the question: Jon pushes a lawnmower with a force of 50.0 n directed at 50 degrees from the horizontal. the lawn mower moves 90.0 m. if jon took 10.0 minu

get priceEmail Contact11/02/2014 Work Problem -- Pushing a lawnmower 1. A lawn mower (25kg) is pushed a horizontal distance of 10m by a 50 N downward force directed 60 degrees to the horizontal. The coefficient of kinetic frictional force is .017. What is the work done by each of the external forces on the lawn mower...

get priceEmail ContactQuestion: Mona is cutting the grass using a 50.0-kg human-powered lawn mower. She pushes the mower with a force of 150 N directed at an angle of 30° below the horizontal direction. Calculate the work Mona does on the mower each time she pushes it 10.0 m across the yard. O - 648 J - 980 J N + 1,300 +550J + 980 J - 1300 J + 648 J -550 J

get priceEmail ContactShe pushes the mower with a force of 150 N directed at an angle of 30° below the horizontal direction. Calculate the work Mona does on the mower each time she pushes it 10.0 m across the yard. Question: Mona is cutting the grass using a 50.0-kg human-powered lawn mower. She pushes the mower with a force of 150 N directed at an angle of 30° below the horizontal

get priceEmail ContactA 10-N force is applied to push a block across a friction free surface for a displacement of 5.0 m to the right. See Answer Only F app does work. F grav and F norm do not do work since a vertical force cannot cause a horizontal displacement. See Answer W app = (10 N) * (5 m) *cos (0 degrees) = +50 Joules. A 10-N frictional force slows a moving block to a stop after a

get priceEmail ContactA person pushes a {eq}14 \ kg {/eq} lawn mower at a constant speed with a force of {eq}88 \ N {/eq} directed along the handle which is at an angle of {eq}45^\circ {/eq} to the horizontal.

get priceEmail ContactAns. W = F × d = 25 N × 20.0 m = 50 J 2. A force of 120 N is applied to the front of a sled at an angle of 28.0 above the horizontal so as to pull the sled a distance of 165 meters. How much work was done by the applied force? Ans. W = F •d cos = 120 N • 165 m cos 28.0 = 17,482.36 J 3. A sled, which has a mass of 45.0 kg., is sitting on a horizontal surface. A force of 120 N is

get priceEmail ContactMike is cutting the grass using a human-powered lawn mower. He pushes the mower with a force of 45 N directed at an angle of 41 degrees below the horizontal direction. Calculate the work that mike does on the mower each time he pushes it 9.1 m across the yard. 310 J. a 5.00 kg block of ice is sliding across a frozen pond at 2.00 m/s. A 7.60 N force is applied in the

get priceEmail ContactMike is cutting the grass using a human-powered lawn mower. He pushes the mower with a force of 45 N directed at an angle of 41° below the horizontal direction. Calculate the work that Mike does on the mower each time he pushes it 9.1 m across the yard. 310 J. A 5.00-kg block of ice is sliding across a frozen pond at 2.00 m/s. A 7.60-N force is applied in the direction of

get priceEmail Contact27/03/2018 F_x=35sqrt3 N F_y=35 N To put it shortly, any force F making an angle theta with the horizontal has x and y components Fcos(theta) and Fsin(theta) "Detailed explanation:" He is pulling his dog at an angle of 30 with the horizontal with a force of 70 N There are an x component and a y component to this force If we draw this as a vector, then the diagram

get priceEmail ContactCorrect answer to the question: Jon pushes a lawnmower with a force of 50.0 n directed at 50 degrees from the horizontal. the lawn mower moves 90.0 m. if jon took 10.0 minu

get priceEmail ContactSo for party, the work done is simply the force times that distance co sign of data. And so, in this case, this would be equal in the force of 35 Newtons, time

get priceEmail Contact14/09/2011 12. Two students push on a sled. One pushes with a force of 30. newtons east and the other exerts a force of 40. newtons south, as shown in the topview diagram below. Which vector best represents the resultant of these two forces? (1) (3) (2) (4) 13. Which combination of three concurrent forces acting on a body could not produce equilibrium? (1) 1 N, 3 N, 5 N (3)

get priceEmail ContactAns. W = F × d = 25 N × 20.0 m = 50 J 2. A force of 120 N is applied to the front of a sled at an angle of 28.0 above the horizontal so as to pull the sled a distance of 165 meters. How much work was done by the applied force? Ans. W = F •d cos = 120 N • 165 m cos 28.0 = 17,482.36 J 3. A sled, which has a mass of 45.0 kg., is sitting on a horizontal surface. A force of 120 N is

get priceEmail ContactMike is cutting the grass using a human-powered lawn mower. He pushes the mower with a force of 45 N directed at an angle of 41° below the horizontal direction. Calculate the work that Mike does on the mower each time he pushes it 9.1 m across the yard. 310 J. A 5.00-kg block of ice is sliding across a frozen pond at 2.00 m/s. A 7.60-N force is applied in the direction of

get priceEmail ContactFigure 7.3 Work done by a constant force. (a) A person pushes a lawn mower with a constant force. The component of the force parallel to the displacement is the work done, as shown in the equation in the figure. (b) A person holds a briefcase. No work is done because the displacement is zero. (c) The person in (b) walks horizontally while ...

get priceEmail ContactA person pushes a 17.0 kg lawn mower at constant speed with a force of 74.0 N directed along the handle, which is at an angle of è = 48.0° to the horizontal (b) Calculate the horizontal retarding force on the mower (c) Calculate the normal force exerted . physics. A man pushes a lawn mower on a level lawn with a force of 193 N. If 39% of this force is directed downward, how

get priceEmail Contact27/03/2018 F_x=35sqrt3 N F_y=35 N To put it shortly, any force F making an angle theta with the horizontal has x and y components Fcos(theta) and Fsin(theta) "Detailed explanation:" He is pulling his dog at an angle of 30 with the horizontal with a force of 70 N There are an x component and a y component to this force If we draw this as a vector, then the diagram

get priceEmail Contact23/06/2014 Mike is cutting the grass using a human-powered lawn mower. He pushes the mower with a force of 45 N directed at an angle of 41° below the horizontal direction. Calculate the work that Mike does on the mower each time he pushes it 9.1 m across the yard. A3. A 5.00-kg block of ice is sliding across a frozen pond at 2.00 m/s. A 7.60-N force is applied in the

get priceEmail ContactA 40.0-kg person hangs 70.0 cm from one end while a 55.0-kg person hangs 50.0 cm from the other end. Another person pushes up halfway between the two persons with a force of 127 N. How much weight does each chain... View Answer. A person pushes a 14.0-kg lawn mower at constant speed with a force of F = 88.0 N directed along the handle, which is at an angle of

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